Consider the equation: X2+ 2x – 15 = 0
A) First, use the "completing the square" process to write this equation in the form
(2 + D)2= E

x² + 2x - 15 = 0

x² + 2x + 1 = 16

(x + 1)² = 16

You can then go forward with that to solve it:

x + 1 = √16

x = -1 ± √16

x = -1 ± 4

x = 3, -5

first one because it can't have a fraction in it

step-by-step explanation: