6x — 8y = 50
4х +6y = 22

x = 7, y = - 1

Step-by-step explanation:

Given the 2 equations

6x - 8y = 50 → (1)

4x + 6y = 22 → (2)

Multiplying (1) by 6 and (2) by 8 and adding will eliminate the y- term

36x - 48y = 300 → (3)

32x + 48y = 176 → (4)

Add (3) and (4) term by term to eliminate y

68x = 476 ( divide both sides by 68 )

x = 7

Substitute x = 7 into either of the 2 equations and evaluate for y

Substituting into (2)

4(7) + 6y = 22

28 + 6y = 22 ( subtract 28 from both sides )

6y = - 6 ( divide both sides by 6 )

y = - 1

Solution is x = 7, y = - 1

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.