Which distance measures 5 units? W
Х
ON
0
1
2
3
4.
5
6 7 8
-8 -7 -6 -5 4 -3 -2 -1
the distance between points W and X
the distance between points X and Y
the distance between points X and Z
O the distance between points Y and Z

10a^3+277a^2-132a-792

step-by-step explanation:

(2a+11)(5a-12)(foil)

=10a^2-24a+55a-132 =10a^2+31a-132

(10a^2+31a-132)(a+6)

=10a^3+60a^2+31a^2+186a^2-132a-792 =10a^3+277a^2-132a-792

i hope this is what you are looking for : )

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐

vertical=18cm horizontal=18cm hypotenuse=25.5

step-by-step explanation:

step-by-step explanation: