In a certain county, the number of charter schools is eleven less than twice the number of alternative schools. there are 35 charter schools in the county. which of the following equations would you use to find the number of alternative schools, a, in the county? 2a − 11 = 35 2a = 35 − 11 2(a − 11) = 35 quantity of a minus 11 all over 2 equals 35

the reason why your question keeps getting deleted because this is not a school related question : )

i will answer your question though.

i never tried church's

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3