Five years ago janeta age was one_fifth of her mother'sage .now she is one_third of her mother's age. find their present ages?

J - Janeta's age  M - mother's age

A) (J-5) = .2 * (M-5)

B) J = (1/3) * M

Subtracting 5 from both sides of B:

B) J -5 = (1/3)M -5

then we substitute the right side of this into the left side of A and we get

(1/3)M -5 = .2 M -1

.333333333333M -5 = .2M -1

.1111111111111111111M = 4

Mother's Age = 36

Janeta's Age = 12

Step-by-step explanation:

answer: our required factorization will be

(3x+4)(x²-5)

step-by-step explanation:

since we have given that

now, we will write it as :

so, we get

5(3x+4)

similarly,

here, we get,

2(3x+4)

together it becomes,

hence, our required factorization will be

(3x+4)(x²-5)