Find x.

x ≈ 15.5 in

Step-by-step explanation:

Given a tangent and a secant from an external point to the circle, then

Th square of the tangent is equal to the product of the external part of the secant and the entire secant, that is

x² = 10(10 + 14) = 10 × 24 = 240 ( take the square root of both sides )

x = ≈ 15.5 in ( to the nearest tenth )

were is the equation

a) y = -3x +2

b) y = 1/2x -6

these 2 can be combined into one equation.

-3x +2 = .5x -6

8 = 3.5x

x = 8 / 3.5 = 2.2857142857

y = -3 * (8 / 3.5) +2

y = (-24 / 3.5) + 2

y = -4.8571428571

step-by-step explanation: