Lines CD and DE are tangent to circle A shown below: If Arc CE is 112°, what is the measure of ∠CDE? a 124° b 136° c 68° d 56°

The measure of ∠CDE is 68degrees

This question bothers on circle geometry;

From the diagram, we can see that ACDE will form a quadrilateral. Since the sum of angles of a quadrilateral is 360degrees, hence;

From the diagram, since CD and DE are both tangential to the circle at point C and E, this shows that <E = <E = 90°

substituting the given values in the formula;

Hence the measure of ∠CDE is 68 degrees

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C

Step-by-step explanation:

The central angle of this is 112 degrees. That is CAE is 112 degrees. That being the case, CDE is 90 + 90 + 112  = 292 Tangents make a 90 degree angle with the center of the circle.

CDE = 360 - 292 = 68

C

(0.2)+(-8)=0.3+-3+0.3m is the equation i guess? ?

step-by-step explanation:

my guess would be b and d, but i didn’t actually get out the pen and paper. lol