Mathematics, 25.01.2021 09:30 ashleyc2442
A metalworker has a metal alloy that is 20% copper and another alloy that is 60% copper. How many kilograms of each alloy should the metalworker combine to
create 60 kg of a 52% copper alloy?
The metalworker should use ? kilograms of the metal alloy that is 20% copper and ? kilograms of the metal alloy that is 60% copper.
(Type whole numbers.)
Answers: 3
Mathematics, 21.06.2019 16:30
Refer to the table below if needed. second quadrant third quadrant fourth quadrant sin(1800- - cos(180° -) tan(180°-e) =- tane cot(1800-0) 10 it to solo 888 sin(180° +c) = - sine cos(180° +) =- cose tan(180° +c) = tane cot(180° +o) = cote sec(180° + c) = - seco csc(180° +2) = - csce sin(360° -) =- sine cos(360° -) = cose tan(360° - e) =- tane cot(360° -) = -cote sec(360° -) = seco csc(360° -) = csco sec(180° -) = csc(180° -) = csca 1991 given that sine = 3/5 and lies in quadrant ii, find the following value. tane
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A metalworker has a metal alloy that is 20% copper and another alloy that is 60% copper. How many ki...
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