F(x)= (x-1)(x(x+1)+2x) find all rational zeros

x = 0, x = 1, x = - 3

Step-by-step explanation:

To find the zeros, let f(x) = 0 , that is

(x - 1)(x(x + 1) + 2x) = 0  ← distribute and simplify parenthesis

(x - 1)(x² + x + 2x) = 0

(x - 1)(x² + 3x) = 0 ← factor out x from the second parenthesis

x(x - 1)(x + 3) = 0

Equate each factor to zero and solve for x

x = 0

x - 1 = 0 ⇒ x = 1

x + 3 = 0 ⇒ x = - 3

the circle one