Need help due in 30 mins​

1. v₂ = 12.43 m/s

2. I₁ = - 80 N.s

3. I₂ = 80 N.s

Explanation:

Consider the following data given in the question:

m₁ = mass of the Cart 1 = 16 kg

m₂ = mass of the Cart 2 = 7 kg

u₁ = velocity of cart 1 before collision = 4 m/s

u₂ = velocity of cart 2 before collision = 1 m/s

v₁ = velocity of cart 1 after collision = - 1 m/s

v₂ = velocity of cart 2 after collision = ?

1.

Applying the law of conservation of momentum:

v₂ = 12.43 m/s

2.

Impulse of cart 1 = I₁ = m₁(v₁ - u₁)

I₁ = (16 kg)(- 1 m/s - 4 m/s)

I₁ = - 80 N.s

3.

Impulse of cart 2 = I₂ = m₂(v₂ - u₂)

I₂ = (7 kg)(12.43 m/s - 1 m/s)

I₂ = 80 N.s

volts times amps 6 x 0.5 3w

it has to be b, about 97 percent.