What is the solution to this system of equations? 2t + w = 10 4t = 20 − 2w A. It has no solution. B. It has infinite solutions. C. It has a single solution: t = 4, w = 2. D. It has a single solution: t = 2, w = 6. E. It has a single solution: t = 6, w = -2.

Step-by-step explanation:

Given the system of equations:

2t + w = 10 1

4t = 20 − 2w ... 2

From 1:

w = 10-2t ...3

Substitute 3 into 2 to have;

4t = 20 - 2(10-2t)

4t = 20-20+4t

4t = 4t

Let t = k

Substitute t = k into 1 and get w;

From 1: 2t + w = 10

2k + w =10

w = 10 - 2k

k can take any integers. This shows that the solution to the equation is infinite

70

step-by-step explanation:

2*5=10

4*15=60

60+10=

70

not sure but it may be b, as i said i'm not sure.