What has a quotiont of 9 and a reminder of 5

Division problems with quotient of 9 and remainder of 5 could include:-

23/2 = 9 + 5/2

32/3 = 9 + 5/3

41/4 = 9 + 5/4

50/4 = 9 + 5/5

But you could justifiably object that more natural forms for the answers would be 11 + 1/2, 10 + 1/3, 10 + 1/4 and 10 , and so you may well prefer such as

59/6 = 9 + 5/6

77/8 = 9 + 5/8  ….. and so on

As you can see the general pattern is (9n + 5)/n = 9 + 5/n

You can now make up your own examples, like 212/23 = 9 + 5/23

Step-by-step explanation:

< xcy ≅ < xby

step-by-step explanation:

in δcax and δbax,

so, δcax ≅ δbax (side-angle-side or sas)

since δcax ≅ δbax, we can conclude < acx ≅ < abx

in δacy and δaby,

so, δacy ≅ δaby (side-angle-side or sas)

since δacy ≅ δaby, we can conclude < acy ≅ < aby

now,

< acy ≅ < aby

=> < acx + < xcy ≅ < abx + < xby

=> < acx + < xcy ≅ < acx + < xby   (since < acx ≅ < abx already proved above)

subtracting < acx from both sides, we get

< acx + < xcy -< acx ≅ < acx + < xby -< acx

cancelling out < acx and -< acx from both sides, we get

< xcy ≅ < xby (proved)