a pile of coins, consisting of quarters and half dollars is worth $11.75. If there are 2 more quarters than half dollars, how many of each are there?

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Step-by-step explanation:

Let the number of half dollars be x,

number of quarters = x + 2

amount of half dollars = 0.5x

amount of quarters = 0.25(x + 2)

= 0.25x + 0.5

total amount = 0.5x + 0.25x + 0.5

= 0.75x + 0.5

0.75x + 0.5 = 11.75

0.75x = 11.25

x = 15

number of quarters = x + 2

= 15 + 2

= 17

There are 17 quarters and 15 half dolla

false

step-by-step explanation:

the reason i say this is because for a certain length of sides you can pick any two and the length is wither equal or greater than the third side and in this case it's not.

3 + 5 = 8

8 is smaller than 9 which is the third side.

hope this : )