what is an equation of the line that passes through the point (-6, -2) and is parallel to the line 3x - 2y = 2

Step-by-step explanation:

Ok, first put the equation into y=mx+b form

3x-2y=2

subtract 3x from both sides

-2y=-3x+2

divide by -2

y=3/2x-1

Parallel lines have the same slope, but a different y intercpet.

So the new equation so far is y=3/2x+b

Since the line has to pass through the given point, substitute (-6,-2) into the equation

-2=3/2(-6)+b

-2=-9+b

7=b

so the line is y=3/2x+7

i believe that the answer is

b. y-1=-2(x-4)

hope this !

think the answer would beb