-4(-6y – 3) = 12 What is the value of y?

y=0

Step-by-step explanation:

So you would do -4(6y-3) and divide that by -4

then you would do 12 and divide that by -4

or

You could do

-6y-3 which equals -3

then

add three to both sides like this -6y-3+3=-3+3

then simplify it to -6y=0

then divide -6y over -6 and 0 over -6

then it will simplify to 0

x = ± 6i

step-by-step explanation:

x^2 = -36

take the square root of each side

sqrt(x^2) = sqrt(-36)

we know sqrt(ab) = sqrt(a) sqrt(b)

x = ±sqrt(36) sqrt(-1)

we know that sqrt (-1) = i

x = ± 6i

set each factor equal to 0

4x-3 = 0

2x-1 = 0

solve for x.

4x-3=0

4x=3

x= 3/4

solve for x. 

2x-1= 0

2x= 1

x= 1/2

eventually after a few more steps, your answer should be 1/2 is less than or equal to x and 3/4 is greater than or equal to x