Hi, can you help me with this please? You can jog at a speed of 7 miles per hour and run at a speed of 12 miles per hour. If you traveled 8 miles in 50 minutes, find the amount of time you jogged as well as the amount of time you ran.

He jogged for 24 minutes and ran for 26 minutes

Step-by-step explanation:

Mathematically,

distance = speed * time

Let the amount of time jogged be x and the amount of time ran be y hours

50 minutes to hours = 50/60 = 5/6

so x + y = 5/6

Total distance jogged is 7x and total distance ran is 12y

7x + 12y = 8

So we have two equations;

x + y = 5/6

7x + 12y = 8

From i, x = 5/6-y

So;

7(5/6 - y) + 12y = 8

35/6 - 7y + 12y = 8

Multiply through by 6

35 + 30y = 48

30y = 13

y = 13/30

13/30 in minutes is 13/30 * 60 = 26 minutes

So the amount of time jogged is 50-26 = 24 minutes

answer

you start with $5 and save $10 a week until you have at least $45wer

step-by-step explanation:

< xcy ≅ < xby

step-by-step explanation:

in δcax and δbax,

so, δcax ≅ δbax (side-angle-side or sas)

since δcax ≅ δbax, we can conclude < acx ≅ < abx

in δacy and δaby,

so, δacy ≅ δaby (side-angle-side or sas)

since δacy ≅ δaby, we can conclude < acy ≅ < aby

now,

< acy ≅ < aby

=> < acx + < xcy ≅ < abx + < xby

=> < acx + < xcy ≅ < acx + < xby   (since < acx ≅ < abx already proved above)

subtracting < acx from both sides, we get

< acx + < xcy -< acx ≅ < acx + < xby -< acx

cancelling out < acx and -< acx from both sides, we get

< xcy ≅ < xby (proved)