A motorbike travels a distance of 110m to the nearest 10 meters, in a time of 5 seconds to the nearest second. Calculate the maximum and minimum values for the speed, s in meters per second (m/s), using
the formula s = where d is the distance and t is the time.

S = 20.46m

Explanation:

According to Second Law of Motion:

S = Vi*t + 0.5*a*t^2

Data:

Vi = 3m/s

a = 9.3m/s^2

t = 1.8s

S = ?

Solution:

S = 3*1.8 + 0.5*9.3*1.8^2

S = 5.4 + 15.06

S = 20.46m

Step-by-step explanation:

well my understanding of this question is they want you to use the y=14.1x -2.3 and put the coordinates they gave you onto the line segment of   y=14.1x -2.3

step-by-step explanation: