Quadrilateral ABCD undergoes a reflection across the x-axis to form quadrilateral a b c d the coordinates of a r the reflected quadrilateral a b c d is then translated three units to the right and third and two units up to form quadrilateral a quotation b quotation quotation see quotation

Solution :

From the figure,

The coordinates of --

A = (-5,-3)

B = (-6,-1)

C = (-3,-1)  

D = (-2,-3)

When it undergoes reflection about x-axis, we have the coordinates of the quadrilateral as

A' = (-5,+3)

B' = (-6,+1)

C' = (-3,+1)

D' = (-2,+3)

Now A'B'C'D' is translated 3 units to right, so the coordinates will be --

A" = (-2,3)

B" = (-3,1)

C" = (0,1)

D" = (1,3)

When the quadrilateral moves third and two units up, we get

A"' = (3,3)

B"' = (2,1)

C"' = (5,1)

D"' = (6,3)

answer

a the answer hopes this

step-by-step explanation:

step-by-step explanation:

use pothagarean therom

a^2+b^2=c^2 so first ac

acm is a right triangle because c= 90°

and am (the hypotenuse or c) =16+9 =25

but there is not enough info we need another angle or side length