Figure EFGH is transformed to E′F′G′H′, as shown: A coordinate plane is shown. Figure EFGH has vertices E at negative 5 comma 4, F at negative 5 comma 1, G at negative 3 comma 2, and H at negative 1 comma 6. Figure E prime F prime G prime H prime has vertices at E prime 7 comma 4, F prime 7 comma 1, G prime 5 comma 2 and H prime 3 comma 6.
Which of the following sequences of transformations is used to obtain figure E′F′G′H′ from EFGH? (4 points)

Question 4 options:

1)

Counterclockwise rotation by 90 degrees about the origin followed by a translation right by 2 units

2)

Counterclockwise rotation by 90 degrees about the origin followed by a translation left by 2 units

3)

Reflection about the y-axis followed by a translation right by 2 units

4)

Reflection about the x-axis followed by a translation left by 2 units

or

step-by-step explanation:

we need to solve for 'x' the following equation:  

we have that:

⇒

⇒ ⇒

factorizing, we get that:

  ⇒

then, the solutions are: or

nothing extraneous has been found!

x coordinate is none

step-by-step explanation:

the correct option is:

b. a value of the variable that makes the polynomial equal to zero.

the root or roots of a polynomial are the values of the variable that makes the polynomial equal to 0. we can find the roots of a polynomial making the expression equal to 0 and then, isolating the variable (it it has just one variable).

for example, given the following polynomial:

the root or zero of the polynomial, can be found by making the expression equal to 0, and then, isolating the variable, so, finding the root we have:

therefore, we have that the root of the polynomial is equal to 2.

we must remember that the number of roots that a polynomial can have, will depend on the degree of the polynomial, a first degree polynomial have will have one single root, a second degree polynomial (quadratic expression) may have two roots and so.

hence the correct option is:

b. a value of the variable that makes the polynomial equal to zero.

have a nice day!

27/4x^6 y^8

step-by-step explanation:

4(3x^2y^4)^3 (2x^3y^5)^4

=

108x^6 y^12 /16x^12 y^20

=

108 /16x^6 y^8

=

27 /4x^6 y^8