Find three consecutive odd integers such that the sum of the smallest number and twice the middle number is 10 more than the largest number.

The three consecutive odd numbers are 5 , 7 , and 9 .

Step-by-step explanation:

Let the three consecutive odd integers be x, x+2 , x+4

Smallest number = x

Middle number = x+2

Largest number = x+4

As per given,

(Smallest number )+ 2 (Middle number ) = 10 + (Largest number)

Hence, Smallest number = 5

Middle number = 5+2 = 7

Largest number = 5+4 =9

hence, the three consecutive odd numbers are 5 , 7 , and 9 .

-22

times both sides by 2, times () by 8, add alile terms, move terms, add alike and caculate divide both sides by 3

you could deduce the conclusion directly using the facts pertaining to the specific situation.

hope this .