3 QUESTIONS ! 1) I picked a number between 1 and 20. I multiplied my number by 6, added 8, divided it by 4, and then subtracted 5. This resulted in the number 3. What was my number?

2) I selected a number between 40 and 50. I divided my number by 9, subtracted 8, added 6 and then multiplied by 7. This resulted the number 21. What was my original number?

1) I picked a number between 100 and 110. I subtracted 4, added 11, multiplied it by 2, divided it by 6, and then subtracted 8. This resulted in the number 29. What was my original number?

1) 4

2) 45

3) 104

Step-by-step explanation:

1)

let x be your number.

((6x+8)/4)-5 = 3

add 5

(6x+8)/4=8

multiply by 4 to get rid of the denominator

6x+8=32

subtract 8

6x=24

divide by 6

x=4

2) Same type. (this time I won't explain every step)

let x be your number

((x/9)-8+6)*7 =21

(x/9)-8+6=3

(x/9)-2=3

x/9 = 5

x=45

3) Same type... Again

let x be your number

(((x-4+11)*2)/6)-8 = 29

((x-4+11)*2)/6=37

(x-4+11)*2 = 222

x+7=111

x= 104

given that triangle abc is transformed two times to get triangle

a"b"c"

first abc is transformed in to a'b'c' as follows:

the coordinates of a are (1,-1) and transformed into a'(-1,1)

similarly b (4,-2) became b'(-4,2) and

c(7,-2) became c'(-7,2)

i.e. (x,y) becomes (-x,-y)

this is nothing but reflection about a point here origin.

thus first transformation is reflection on the origin.

next is exactly shifting 3 units down

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