Given f(x) = 3(x2 - 5) + 1 Find f(-3)

f(-3) = -32 for f(x) = 3(2x - 5) + 1

f(-3) = 13 for f(x) = 3(x^2 - 5) + 1

Step-by-step explanation:

f(x) = 3 (2x - 5) + 1

f(-3) = 3 (2(-3) - 5) + 1

f(-3) = 3( -6 - 5 ) + 1

f(-3) = 3( -11 ) + 1

f(-3) = -33 + 1

f(-3) = -32

f(x) = 3(x^2 - 5) + 1

f(-3) = 3((-3)^2 - 5) + 1

f(-3) = 3(9 - 5) + 1

f(-3) = 3(4) + 1

f(-3) = 12 + 1

f(-3) = 13

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