On a canoe trip, Rita paddled upstream (against the current) at an average speed of 2mi/h relative to the riverbank. On the return trip downstream (with the current), her average speed was 3 mi/h. Find Rita's paddling sp eed in still water and the speed of the river's current.

Paddling speed = 2.5mi/h

speed of current = 0.5mi/h

Step-by-step explanation:

Given that :

Paddling upstream against current (paddling speed - speed of current)

Let paddling speed be, x ; current speed = c

x - c = 2mi/h - - - (1)

Return downstream (paddling speed + speed of current)

x + c = 3mi/h - - - - (2)

Add (1) and (2)

2x = 5

x = 5/2 = 2.5

Paddling speed = x = 2.5mi/h

Speed of current :

From;

x + c = 3

2.5 + c = 3

c = 3 - 2.5

c = 0.5

c = speed of current = 0.5mi/h

explanation:

previous steps have made pa≅ pb ≅ st ≅ su. setting the compass width to ab allows you to make tu the same length. then δstu ≅ δpab by the sss congruence postulate, and ∠p ≅ ∠s by the reason cpctc.

∈3,600

step-by-step explanation: