In ΔEFG, {EG}EG is extended through point G to point H, m∠ EFG = (2x+1) m∠EFG=(2x+1), m∠ FGH = (6x+2) m∠FGH=(6x+2), and m∠ GEF = (x+19) m∠GEF=(x+19). Find m∠ GEF.

Answer the questions in the attachment. a rescue helicopter is at point a and a rescue boat is at point e. the helicopter pilot spots boats in distress at points d and c,with angles as marked in the diagram. figure abce is a rectangle. the altitude of the rescue helicopter, represented by ae, is 5000 feet.

What is the anwers for 9+2x=5x-3-x

Examine the paragraph proof. which theorem does it offer proof for? prove jnm – nmi according to the given information in the image. jk | hi while jnm and lnk are vertical angles. jnm and lnk are congruent by the vertical angles theorem. because lnk and nmi are corresponding angles, they are congruent according to the corresponding angles theorem. finally, jnm is congruent to nmi by the transitive property of equality alternate interior angles theorem gorresponding angle theorem vertical angle theorem o same side interior angles theorem