Summer is tossing a softball into the air with an underhand motion. The distance of the ball above her hand at any time is given by the formula: h(t)= 128t-16t^2 for 0<_t<_8 Where h(t) is the height of the ball (in feet) and t is the time (in seconds)

At what times, t, is the ball in her hands? Note: There are 2 different times.

At what times, t, is the ball at it's maximum height?

How high. h, is the ball at it's maximum height?

answer: 5

step-by-step explanation:

since, the range is the difference between the lowest and highest values of the given sample space.

and, here the sample space = { 3, 1, 0, 4, 1, 4, 2, 3, 0, 5, 0, 1, 1, 2, 0, 4, 1,4, 4 ,2 ,3 ,2 ,0 ,1 ,4 }

here, the highest value of the given sample = 5

and, the lowest value = 0

therefore, the range of the sample space = 5 - 0 = 5

the answer is a) y= 2 csc [0.5 (x+pi/2)]-1

step-by-step explanation:

this is a direct variation proportion. y = kx

y is the total amount due, k is the constant of variation, and x is the number of texts sent.

plug in the 3.20 and the 16 to solve for the "k". this is the constant of proportionality. it is the value that will not change.

3.20 = k(16). solving you get $.20 per text.

the equation would then be y = .20x