On a hot summers day, 613 people used the public swimming pool. The daily prices are 1.75 dollars for children and 2 dollars fir adults. The recipts for admission totaled 1127 dollars. How many children and how many adults swam at the public pool that day?

396  children and 217 adults swam at the pool.

Step-by-step explanation:

Step 1

let Children be represented as  x

and Adults  be represented as y

therefore

Step 2

x + y =  613equation 1 represents the 613 people (children and adults) that used the public swimming pool.

And

1.75x + 2.00y = 1127... equation 2represents the daily prices which totaled 1127 dollars

Making x subject formulae in equation 1 and substituting in equation 2

x= 613-y

1.75(613-y) + 2.00y = 1127

1072.75 -1.75y+ 2y=1127

1127-1072.5 = -1.75y +2y

54.25=0.25y

y=54.25/0.25

y=217

Substitute y = 218 in (1)

x + 217= 613

x = 613-217

x = 396

396  children and 217 adults swam at the pool.

396 children and 217 adults tickets were sold at the pool.

Step-by-step explanation:

Given data:

Number of people who used the pool = 613

Total sum on the receipt = 1127.

Price of adult tickets = $2

Price for children tickets = 1.75

Solution:

Let

Children = x

Adults = y

x + y = 613 equation 1

1.75x + 2y = 1127 equation 2

Multiply equation (1) by 2

2x + 2y = 1226 equation 3

1.75x + 2y= 1127

Subtract (2) from (3)

0.25x = 99

x = 396

Substitute x = 396 in equation (1)

x + y = 613

396 + y = 613

y = 217

396 children and 217 adults tickets were sold at the pool.

may i see the picture? it would a lot, xox