Find the equation for a line in slope-intercept form that goes through the points (-3, -2) and (3, 16)

y = 3x+7

Step-by-step explanation:

The standard form of equation in slope-intercept form is:

y = mx+c

m is the slope

c is the intercept

Given the coordinates (-3, -2) and (3, 16)

Get the slope;

Slope = ∆y/∆x

Slope = y2-y1/x2-x1

Slope = 16-(-2)/3-(-3)

Slope = 16+2/3+3

Slope = 18/6

Slope = 3

Get the Intercept

Substitute one of the points in the formula:

Using the coordinate (-3, -2)

y = mx+c

-2 = 3(-3)+c

-2 = -9 + C

c = -2+9

c = 7

Get the equation of the line by substituting m and c into the equation y = mx+c

y = 3x+7

answer: list the statements and i will follow up!

step-by-step explanation:

the image is given below

since the options are not given so we draw it from the equation

the given equation is

y = (x-1) (x+4)

y = y² + 3x - 4

the above equation is a quadratic equation which will have two roots. if we draw the graph for it, it will look like this