Question 2 Multiple Choice Worth 1 points) (02.01 MC)
A triangle has vertices at B(-3,0), C(2, -1), D(-1,2). Which series of transformations would produce an image with vertices B"(4. 1). C*(-1,0), D (2. 3)?
O(x, y) — (X. -Y). (x, y) - (x + 1, y + 1)
O (X, ) – (-x, y). (X. y) - (x + 1, y + 1)
O(x, y) - (x, y), (x, y) - (X + 2, Y + 2)
(x, y) - (-x, y). (x, y) = (x + 2 y + 2)

he has now walked a total of what?

if i know what this is maybe i can

step-by-step explanation:

we have three similar triangles, because each has a right angle and shares an angle.   let's write the angles in order: opposite to short leg, long leg, hypotenuse.

cab similar to bad similar to cbd

or as ratios,

ca: ab: cb = ba: ad: bd = cb: bd: cd

we also know

ac = ad + cd

(ad+cd): ab: cb = ba: ad: bd = cb: bd: cd

(ad+cd)/cb=cb/cd

we have cb=6, ad=5 and seek x=cd.

we reject the negative root and conclude x=4

answer: 4

i need points

step-by-step explanation:

sorry bubs