Help me please.

9514 1404 393

Step-by-step explanation:

The applicable rules of exponents are ...

  (a^b)(a^c) = a^(b+c)

  a^0 = 1 . . . . for a ≠ 0

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And, it is convenient to know the cubes of small integers:

  1³ = 1; 2³ = 8; 3³ = 27; 4³ = 64; 5³ = 125

  6³ = 216; 7³ = 343; 8³ = 512; 9³ = 729; 10³ = 1000

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1) p^3 × p^5 = p^-12 × p^y

Equating exponents:

  3 + 5 = -12 + y

  20 = y . . . . . . . . . . . add 12

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2) 64 × 4^5 = 4^3 × 4^5 = 4^(3+5) = 4^8

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3) 10^x = 1 = 10^0

  x = 0

okay so i did it and i got these answers

- y = 20

- 4^8

- x = 0

step-by-step explanation:

my work

- p^3 × p^5 = p^-12 × p^y then 3 + 5 = -12 + y so: 20 = y

64 × 4^5 = 4^3 × 4^5 = 4^(3+5) so: its 4 over 8

10^x = 1 = 10^0 so: its 0

hope this helped :) pls give me brainliest <3

answer are

step-by-step explanation: