A small, old bridge is susceptible to damages from heavy trucks. Suppose the bridge can have room for at most two trucks, one in each lane. It can easily carry one truck, but it may be damaged when two trucks are present, and this depends on the extent of overloading. The damage probability is: 0.3 when both trucks are overloaded, when one truck is overloaded, and when neither truck is overloaded. The fraction of trucks that are overloaded is . You can assume that the overloading of any two trucks has no relationship, and that there is no possibility of damage when only one truck is on the bridge (therefore, we look for damage only when two trucks are present, with any of them overloaded or both of them overloaded or none of them overloaded). What is the probability of damage to the bridge while two trucks are on it

true

explanation:

1. 3. can also be expressed as (22/7)

2. -4.5

3. 3.6

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pls mark as brainliest

they used 313 gallons of paint

step-by-step explanation:

part a. the differences are decreasing, so we know the sequence is not arithmetic. the ratios are constant (=3/4), so we know the sequence is geometric.

part b. from part a, we know the common ratio is 3/4, so each term is 3/4 of the one before. the initial term is the number of gallons at h=1.

g[h] = (3/4)·g[h-1]

g[1] = 384 . . . . initial value required for a recursive definition

part c. the general formula for a geometric sequence is

a[n] = a[1]·r^(n-1)

we have a[1] = 384, r = 3/4, and the term number given by h. the formula that follows is

g[h] = 384·(3/4)^(h-1)

part d. filling in the value and doing the arithmetic, we have

g[12] = 384·(3/4)^11 ≈ 384·0.042235136 ≈ 16.2183 . . gallons

part e. each gallon is 4 quarts, so

16.2183 gal × 4 qt/gal = 64.8732 qt