A television game show has 11 doors, of which the contestant must pick 3. Behind 3 of the doors are expensive cars, and behind the other 8 doors are consolation prizes. The contestant gets to keep the items behind the 3 doors she selects. Determine the probability that the contestant wins at least one car.

For there to be 1 car, we consider two possible outcomes:

The first door opened has a car or the second door opened has a car.

P(1 car) = 2/6 x 4/5 + 4/6 x 2/5

P(1 car) = 8/15

For there to be no car in either door

P(no car) = 4/6 x 3/5

P(no car) = 2/5

Probability of at least one car is the sum of the probability of one car and probability of two cars:

P(2 cars) = 2/6 x 1/5

= 1/15

P(1 car) + P(2 cars) = 8/15 + 1/15

= 3/5

the function makes a strait line horizontally with no x intercept but a y intercept at 9.

step-by-step explanation:

points a and b are equidistant from the desired line, so the line you find by using them will go through point r.

using points other than a and b will give the desired line only if they are equidistant from r. if they are randomly located, the perpendicular line you create will not necessarily go through point r, hence will not be a solution to the problem.