Write an equation of the quadratic function that has x-intercepts 5-i√2 and 5+i√2

f(x) = x² - 10x + 27

Step-by-step explanation:

Given the x- intercepts of f(x) are x = a and x = b, then the factors are

(x - a) and (x - b) and f(x) is the product of the factors, that is

f(x) = (x - a)(x - b)

Here the x- intercepts are 5 - i and 5 + i , thus the factors are

(x - (5 - i )) and (x - (5 + i )) , that is

(x - 5 + i) and (x - 5 - i , then

f(x) = (x - 5 + i )(x - 5 - i ) ← expand using FOIL

     = (x - 5)² - 2i² ← i² = - 1

     = x² - 10x + 25 + 2

     = x² - 10x + 27

what?

step-by-step explanation:

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