Name the line of reflection used to map each pre-image to its image.
Please help

Step-by-step explanation:

From the picture attached,

9). When pre-image KLMN is a reflected across x = -2, we get image K'L'M'N'.

    Therefore, line of reflection will be x = -2

10). In this picture line of reflection which passes through origin (0, 0) and slope = 1 will be,

y = x.

11). Since, all the points of image and preimage points are equidistant from x-axis, line of reflection will be x-axis or y = 0.

12). Line passing through midpoint of the line joining BB' will be the line of reflection.

Coordinates of B → (5, 3)

Coordinates of B' → (5, 7)

Coordinates of BB' → → (5, 5)

Therefore, line of reflection will be y = 5.

13). Coordinates of G → (2, 5)

     Coordinates of G' → (-2, 5)

     Midpoint joining the segment GG' → → (0, 5)

     Therefore, line of reflection → x = 0

14). Line of reflection passing through (0, 0) and slope = -1

     y = -x

∠lno ≅ ∠lnm

∠oln ≅ ∠mln

step-by-step explanation:

given   that triangle lno is congruent to triangle lnm.

we have to fill up the blanks in the given question.

according to above order of congruency   kept in mind we can say that

∠lno ≅ ∠lnm

∠oln ≅ ∠mln

ln ≅ ln due to common in both.

hence, by sas congruency,

the side angle side rule   states that if two sides and the included angle of one triangle are congruent to another triangle, then these two triangles are congruent.

inverse property is the answer

step-by-step explanation: