A ball is thrown upward with an initial velocity of 11 meters per second. Suppose that the initial height above the ground is 6 meters. At what time will the ball hit the ground? The ball is on the ground when s=0. Use the equation s=-5t^2+vt+h

25.2

step-by-step explanation:

2+4x6-8/10= 25.2

5+2x=a

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answer:

given the linear inequality :

add 2y to both sides we get;

simplify:

add 12 to both sides of an equation;

simplify:

divide both sides by 2 we get;

or

the related equation for the inequality equation [1] is;

y-intercepts defined as the graph crosses the y-axis.

substitute x =0 in [2] to solve for y;

y = 6

x-intercepts defined as the graph crosses the x-axis.

substitute value y = 0 to solve for x;

subtract 6 from both sides we get

multiply both sides by 2 we get;

or

x = -12

now, plot these point (0, 6) and (-12, 0) on graph as shown below and shade the graph below the solid line.