The length of a rectangle is 8 feet more than the width. if the width is increased by 4 feet, and the length is decreased by 5 feet, the area remains the same. find the dimensions of the original rectangle.

Width = 12 feet

Length = 20 feet

Step-by-step explanation:

The area of a rectangle is A = l*w. Here the length is 8 feet more than the width or 8 + w and the width is w. So the area is A = w(8+w) = 8w + w²

If the dimensions are changed then the expressions will change. The width is increased by 4 feet. This means the width w becomes w + 4. The length is decreased by 5 feet. This means the length becomes 8 + w - 5 = 3 + w. So the area of the new triangle is A = (w+4)(3+w) = w² + 7w + 12.

Since the areas are the same, set them equal to each other and solve for w.

w² + 7w + 12 = 8w + w²                Subtract w² from both sides.

7w + 12 = 8w                                 Subtract 7w from both sides.

12 = w

The original width w is 12 feet. This means the original length which was 8 + w = 8 + 12 = 20 feet.

rectangle: 9 1/8 x 4 1/9 = 37 37/72in

parallelogram: b times h= 10.3 x 6.2 = 63.86

trapezoid: a+b/2 times h= 42.5

volume of prism: l times w times h= 36

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step-by-step explanation:

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