Lines AB and CD are parallel. Find the measures of the three angles in triangle ABF.

m(∠FBA) = 42°

m(∠FAB) = 23°

m(∠AFB) = 115°

Step-by-step explanation:

Lines AB and CD are parallel.

m(∠FCD) = m(∠FBA) = 42° [Alternate interior angles]

m(∠CDF) + m(∠CDE) = 180° [Linear pair of angles]

m(∠CDF) = 180° - 157°

               = 23°

m(∠CDF) = m(∠BAF) = 23° [Alternate interior angles]

m(∠AFB) + m(∠FBA) + m(∠BAF) = 180° [Sum of interior angles of a triangle]

m(∠AFB) + 42° + 23° = 180°

m(∠AFB) = 180° - 65°

               = 115°

Therefore, m(∠FBA) = 42°

                  m(∠FAB) = 23°

                  m(∠AFB) = 115°

answer: i cant see the picture

step-by-step explanation:

can u take a better picture

the correct answer option is (2x-3)(2x+3).

step-by-step explanation:

we are given the following expression and we are to factorize it:

we are to find such factors that when multiplied they give a result of 36 (9 x 4 = 36) and when added they give a result of 0.

the two such factors of 36 are negative six and postive six.

factorizing the given expression to get:

therefore, the correct factorization of is (2x-3)(2x+3).