5x – 2 (2x - 1) = 2 (3x-4)

x = 2

Step-by-step explanation:

5x - 2 ( 2x - 1 ) = 2 ( 3x - 4 )

First we need to distribute from the parenthesis.

5x -4x + 2 = 6x -8

Now look for any numeral that can be added or subtracted that is on the same side, here for example is 5x and -4x.

x + 2 = 6x - 8

Now find the side with the larger x value, and either add or subtract the lingering number on that side, ours here is 8.

x + 2 = 6x - 8

+8         +8

x + 10 = 6x

Near our last few stages subtract or add the smallest value x from the largest.

x + 10 = 6x

-x          -x

10 = 5x

Finally, we divide each side by the number next to x.

10 = 5x

10/5 =2

5x/5 = x

To put our eqaution in correct form we write

x = 2

Hope this helps :)

can someone answer this question plz

step-by-step explanation:

the correct functions are

h(x) = 3x + 2  

g(x) = 2^x

step-by-step explanation:

i proceed to calculate the different values ​​of k (x)

case 1)  k(x) = g(x) ∘ h(x)

g(x) ∘ h(x)=g(h(x))

k(x) = [2]^[3x + > is the option  4. k(x) = 2^(3x + 2 )

case 2)  k(x) = g(x) + h(x)

k(x) = [2^x]+[3x + 2]=2^x+3x+> is the option  1.) k(x) = 2^x + 3x + 2

case 3)k(x) = h(x) ÷ g(x)

k(x) =  [3x + 2]/[2^x]=3x/(2^x)+2/(2^x)=3x*(2^-x)+2^(1-x)

is the option  3.)   k(x) = (3x)2^(-x) + 2^(-x + 1 )

case 4)k(x) = g(x) - h(x)

k(x) =  [2^x]-[3x + 2]=2^x-3x-> is the option  2.) k(x) = 2^x - 3x - 2 

case 5)  k(x) = g(x) × h(x)

k(x) = [2^x]*[3x + > is the option  5.) k(x) = 2^x(3x + 2)

case 6)k(x) = h(x) ∘ g(x)

h(x) ∘ g(x)=h(g(x))

k(x)=3*[2^x]+> is the option  6. k(x) = 3(2^x) +2