Repeat Question 2 and Question 3 for corresponding points B and BGH, C and CGH, and D and DGH. With your measurements displayed in GeoGebra, move the line of reflection, , around the coordinate plane. Also, move the points of the preimage ABCD as you’d like. Based on your investigation, what can you conclude about the line of reflection with respect to the image and the preimage? Express your answer in geometric terms.

A vertex on polygon ABCD and its corresponding vertex on polygon AGHBGHCGHDGH are always equidistant from the line of reflection. Each of the four line segments (, for example) is perpendicular to and cut in half by the line of reflection, . This means that   is a perpendicular bisector of those line segments.

Step-by-step explanation:

the value of v.w= -12.

step-by-step explanation:

we are given three vector r,v and w as:

r = < 5, -5, -2> ; v = < 2, -8, -8> ; w = < -2, 6, -5>

we know that r,v and w could also be represented as:

r=5i-5j-2k

v=2i-8j-8k

and w= -2i+6j-5k

where i,j and k are the unit vectors of x,y and z-axis respectively.

also we know that it has the following property:

i.i=1 ; j.j=1; k.k=1

and i.=j.i=i.k=k.i=j.k=k.j=0

i.e. when we multiply two vectors or we find it's dot product we need to only multiply the components of x coordinates with each other; y with each other and z with each other.

hence, v.w= (2i-8j- -2i+6j-5k)

                  = 2×(-2)+(-8)×(6)+(-8)×(-5)

                  = -4-48+40

                  = -12

hence, v.w= -12

you cant answer this dummy

step-by-step explanation: