Find the constant of variation for the quadratic variation.

9y = 4x2

a) -2
b) 4/9
c) 2/3
d) 9/4

option B is correct

The constant of variation is, .

Step-by-step explanation:

Since the quadratic variation is the relationship between the variables x and y

i.e, ; where k is the quadratic variation.

Given quadratic equation:    ...[1]

Division property of equality states that you divide the same number to both sides of an equation

Divide both side by 9,we get

On simplifying we get;

Now, compare above equation by equation[1] we get the value of k;

i.e,

Therefore, the constant of variation is, .

find the magnitude of the trig term  

csc

(

x

)

−

1

by taking the absolute value of the coefficient.

1

find the lower bound of the range.

tap for more

y

=

−

2

find the upper bound of the range.

tap for more

y

=

0

the range is  

y

≤

−

2

or  

y

≥

0

.

(

−

∞

,

−

2

]

∪

[

0

,

∞

)

{

y

|

y

≤

−

2

,

y

≥

0

}

step-by-step explanation:

step-by-step explanation: