Spackle paint supply had a beginning inventory of 10 cans of paint at 25 per can. They purchased 20 at 30 per can. They had an ending inventory valued 500. How much paint in dollars was used for the month

The total number of paints used for the month = $350

Step-by-step explanation:

Given that:

Spackle paint had a beginning inventory of 10 can of paint at $25 per can =

10× $25 = $250

They purchased 20 at $30 per can.

The amount of the 20 purchased can = 20 × $30 = $600

The total inventory for this supply = $600 + $250

= $850

They had an ending inventory valued 500.

∴

The total number of paints used for the month = total inventory  - ending inventory

The total number of paints used for the month = $850 - $500

The total number of paints used for the month = $350

90% rotation

step-by-step explanation:

let's add {f(x)=x+1}f(x)=x+1 and {g(x)=2x}g(x)=2x together to make a new function.

f(x)+g(x) =(x+1)+(2x)=x+1+2x=3x+1

let's call this new function hh. so we have:

{h(x)}={f(x)}+{g(x)}{=3x+1}h(x)=f(x)+g(x)=3x+1

we can also evaluate combined functions for particular inputs. let's evaluate function hh above for x=2x=2. below are two ways of doing this.

method 1: substitute x=2x=2 into the combined function hh.

h(x)

h(2)

​    

=3x+1

=3(2)+1

=7

​ since h(x)=f(x)+g(x)h(x)=f(x)+g(x), we can also find h(2)h(2) by finding f(2) +g(2)f(2)+g(2).

first, let's find f(2)f(2):

f(x)

f(2)

​    

=x+1

=2+1

=3

​  

now, let's find g(2)g(2):

g(x)

g(2)

​    

=2x

=2⋅2

=4

​  

so f(2)+g(2)=3+4=\greend7f(2)+g(2)=3+4=7.

notice that substituting x =2x=2 directly into function hh and finding f(2) + g(2)f(2)+g(2) gave us the same answer!