On a coordinate system, a square which lies entirely in quadrant I has a vertex at the origin. Another square, which
lies entirely in quadrant III, also has a vertex at the origin.
If the squares are congruent, this could be shown with all of
the following transformations except-
O translation
O rotation
O reflection
dilation

i dont have an answer

step-by-step explanation:

you already gave the answer

step-by-step explanation:

answer:   28.56 feet (approx)

step-by-step explanation:

since, triangle abc has measure of angle c equal to 55 degrees, measure of angle abc equal to 90 degrees, and length of bc equal to 20 feet.

we have to find out the measurement of segment ab.

therefore, tan 55° =

but bc = 20 feet.

⇒ tan 55 ° =  

⇒ ab = 20 × tan 55 °

⇒ ab = 20 × 1.42814800674

⇒ ab = 28.5629601348   ≈ 28.56 feet