The amount people who pay for cell phone service varies quite a bit, but the mean monthly fee is $55 and the standard deviation is $22. The distribution is not Normal.
Many people pay about $30 for plans with 2GB data access and about $60 for 5GB of
data access, but some pay much more for unlimited data access. A sample survey is
designed to ask a simple random sample of 1,000 cell phone users how much they pay.
Let be the mean amount paid.
Part A: What are the mean and standard deviation of the sample distribution of x with line on top?
Show your work and justify your reasoning.
Part B: What is the shape of the sampling distribution of the mean of the sample? Justify your answer.
Part C: What is the probability that the average cell phone service paid by the sample
of cell phone users will exceed $56? Show your work.

.there can be infinite values of m and n that can satisfy the above equation. for each value of m of m or n. there maybe infinite sets of solution for the above

step-by-step explanation:

step-by-step explanation :

we know that

the measurement of the outer angle is the semi-difference of the arcs which comprises

in this problem

m< xzy is the outer angle

substitute the values

the measure of angle xoy is equal to

> by central angle

substitute the value

hello!

to begin with, we're given that on earth, a rock weighs 20 pounds, and while on jupiter, that same rock weighs 42 pounds. now, we're trying to find the weight of a rock that weighs 10.5 pounds on earth, on jupiter.

to solve this, first, set up a proportion, cross-multiply, and solve it algebraically.

setting up the proportion is the hardest and the most confusing part of the problem, but it's simple.

if on earth, the rock weighs 20 lbs, and on jupiter it weighs 42 lbs, our first part of our proportion is 20/42 lbs. the second part has to be equal to each other. this means that 10.5 has to be on the numerator of the fraction, and x, the value we're trying to find, has to be on the denominator. remember that the rock weighs 10.5 lbs on earth, and we're trying to find the weight of it on jupiter (which is x).

20/42 = 10.5/x

next, you would cross-multiply.

20x = 42(10.5)

20x = 441

now, solve it algebraically by using division.

x = 22.05 lbs

this can be rounded to 22.1 lbs.

therefore, the weight of the rock on jupiter is 22.1 lbs, the fourth choice.