In the diagram, P1P2 and Q1Q2 are the perpendicular bisectors of and , respectively. and are the angle bisectors of ∠A and ∠B, respectively. The center of the inscribed circle of ΔABC is point , and the center of the circumscribed circle of ΔABC is point .

6: 07 is your answer

step-by-step explanation:

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answer:

given the linear inequality :

add 2y to both sides we get;

simplify:

add 12 to both sides of an equation;

simplify:

divide both sides by 2 we get;

or

the related equation for the inequality equation [1] is;

y-intercepts defined as the graph crosses the y-axis.

substitute x =0 in [2] to solve for y;

y = 6

x-intercepts defined as the graph crosses the x-axis.

substitute value y = 0 to solve for x;

subtract 6 from both sides we get

multiply both sides by 2 we get;

or

x = -12

now, plot these point (0, 6) and (-12, 0) on graph as shown below and shade the graph below the solid line.