Enter the coordinates of the vertex of the graph of y=2(x+5)^2

The vertex is ( -5,0)

Step-by-step explanation:

The vertex form of a parabola is

y = a( x-h) ^2 +k

where ( h,k) is the vertex

y=2(x+5)^2

y=2(x - -5)^2 +0

The vertex is ( -5,0)

vertex = (- 5, 0 )

Step-by-step explanation:

The equation of a parabola in vertex form is

y = a(x - h)² + k

where (h, k) are the coordinates of the vertex and a is a multiplier

y = 2(x + 5)² , that is y = 2(x + 5)² + 0 ← is in vertex form

with (h, k) = (- 5, 0 )

check above link.

graphically?   well, you graph them both, the solutions is where they both intersect each other, since there are two solutions, meaning they will meet twice, or namely the linear will run into the quadratic curve twice, and where they meet, those x,y coordinates are the solutions to the system.

none of these

step-by-step explanation:

23 + 34 add up to 57 so just inform the teacher of this really stupid mistake