According to the World Health Organization (WHO) Child Growth Standards, the head circumference for boys at birth is normally distributed with a mean of 34.5cm and a standard deviation of 1.3cm. What is the probability that a boy has a head circumference greater than 36.32cm at birth

0.081

Step-by-step explanation:

To solve this question, we would use the z score formula

z score = (x-μ)/σ, where

x is the raw score = 36.32cm

μ is the population mean = 34.5 cm

σ is the population standard deviation = 1.3cm

z score = (36.32cm - 34.5cm)/1.3cm

z = 1.4

Using the normal distribution to find the z score for 1.4

P(z = 1.4) = 0.91924

Therefore, the probability that a boy has a head circumference greater than 36.32cm at birth is

P(x>36.32) = 1 - P(z = 1.4)

= 1 - 0.91924

= 0.080757

Approximately ≈ 0.081

options a,b,c are the right answer.

step-by-step explanation:

a linear parent function is always represented as y = x

if we write this function in the form of y=mx+c

⇒

or  

now if we plot a graph we will find these characteristics:

1) y intercept of the graph is zero so its a straight line passing through origin.

2) as we can see in both the forms of function written, values of x and y may be either positive or negative for the positive slope means points on the graph are either in first quadrant or in third one.

3) it's slope is one.

logv3(x+2)=1

rewrite in exponential form:

logb(x) = y is equal to b^y =x

b = 3, y = 1

now solve for x:

3^1 = x+2)

x = 3-2

x = 1

see the picture for the graph.