The following two-way frequency table shows information collected from a survey of attendees at a neighborhood meeting regarding how many people have a dog and how many people take walks in the neighborhood. What is the probability that a randomly selected person does not take walks in the neighborhood but has a dog? Write your answer as a fraction in the simplest form, formatted like this: 2/7

the probability that a randomly selected person does not take walks in the neighborhood but has a dog is

Total number of people surveyed = 57 + 21 + 13 + 9 = 100

And, there is 21 does not walk

So, the probability should be

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is the correct answer.

Step-by-step explanation:

As per the Given table, we can say that :

Number of people who have a dog and walk = 57

Number of people who have a dog but do not walk = 21

Number of people who do not have a dog and walk = 13

Number of people who do not have a dog and do not walk = 9

Total number of people surveyed = 57 + 21 + 13 + 9 = 100

Formula for probability of any event E is given as:

Here, we have to find the probability that a randomly selected person does not take walks but has a dog.

Number of favorable cases here = Number of people who does not walk but has a dog = 21

Total Number of cases = Total number of people surveyed = 100

So, required probability is:

So, the answer is .

55% are girls and 45% are boys : ) hope this

step-by-step explanation:

c) yes, because of asa or aas