A newly constructed fish pond contains 3000 liters of water. Unfortunately the pond has been contaminated with 5 kg of a toxic chemical during the construction process. The pond's filtering system removes water from the pond at a rate of 200 liters/minute, removes 50% of the chemical, and returns the same volume of (the now somewhat less contaminated) water to the pond. Write a differential equation for the time (measured in minutes) evolution of:

The differential equation for the time is

The given parameters are:

The differential equation for the time is then calculated as:

Where:

--- the rate in

--- the rate out

Substitute these values in

Hence, the differential equation for the time is

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Step-by-step explanation:

We are given that

Volume of water in fish pond,V=3000 L

Mass of toxic  chemical=5 kg

Rate=200L/min

Removes chemical=50%

We have to find the differential equation for the time.

Let mass of toxic at any time t= m kg

Rate=Rate in-Rate out

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step-by-step explanation:

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