Mathematics, 19.07.2020 01:01 janae789
In a poster making contest, you are required that the rectangular poster must have a perimeter of 34 inches. You need to find the dimensions of the poster if the length is 2 inches more than twice the width.
Answers: 3
Mathematics, 21.06.2019 14:30
Select the correct answer. what is the surface area of the victory podium shown here? include all surfaces of the podium, including the bottom. a. 61.5 square feet b. 61.75 square feet c. 65.25 square feet d. 69 square feet
Answers: 2
Mathematics, 21.06.2019 19:50
Prove (a) cosh2(x) โ sinh2(x) = 1 and (b) 1 โ tanh 2(x) = sech 2(x). solution (a) cosh2(x) โ sinh2(x) = ex + eโx 2 2 โ 2 = e2x + 2 + eโ2x 4 โ = 4 = . (b) we start with the identity proved in part (a): cosh2(x) โ sinh2(x) = 1. if we divide both sides by cosh2(x), we get 1 โ sinh2(x) cosh2(x) = 1 or 1 โ tanh 2(x) = .
Answers: 3
Mathematics, 21.06.2019 23:30
If you measured the width of a window in inches and then in feet with measurement would you have the greater number of units
Answers: 3
In a poster making contest, you are required that the rectangular poster must have a perimeter of 34...
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