Consider the homogeneous second-order linear differential equation y′′+4y′−12y=0. Which of the following pairs gives two solutions to this equation? A. y1=e2x, y2=e−6x B. y1=e3x, y2=e1x C. y1=e2x, y2=e−2x D. y1=e−12x, y2=xe−12x E. y1=cos(−12x),y2=sin(−12x) F. y1=e−4x, y2=e−12x Then for these solutions find a particular solution of the form y=c1y1+c2y2 that satisfies the initial conditions y(0)=−5,y′(0)=0. y = y1 + y2.