The given line passes through the points (-4, -3) and (4. 1)
What is the equation, in point-slope form of the line that is
perpendicular to the given line and passes through the
point (-4, 3)?
V-3 -2(x+4)
3-
2-
+
Oy-3 =-{(x+4)
Ov-3 = {(x + 4)
-2
y-3 =2(x + 4)
-3
(-3)

9514 1404 393

  y -3 = -2(x +4)

Step-by-step explanation:

The slope of the given line is ...

  m = (y2 -y1)/(x2 -x1)

  m = (1 -(-3))/(4 -(-4)) = 4/8 = 1/2

The perpendicular line will have slope -1/(1/2) = -2.

__

The point-slope equation of the line with slope m through point (h, k) is ...

  y -k = m(x -h)

For point (-4, 3) and slope -2, the equation is ...

  y -3 = -2(x +4)

answer

a,b, and d

explanation

a reflection angle is more than

but less than;

an angle that measures

is a reflex angle.(true)

an angle that measures less than

is acute.(true)

provided we are considering angles greater or equal to zero.

an acute angle lies in the range.

an obtuse angle is less than 180° but more than 90°

an angle that measures 300° is obtuse (false)

an angle that measures 65° is an acute angle.(true)